Chlorine gas can be produced by reacting sulphuric acid with a mixture of MnO2 and NaCl- The reaction follows the equation- 2NaCl - MnO2 - 3H2SO4 - 2NaHSO4 - MnSO4 -Cl2 - 2H2OWhat volume of chlorine can be produced from 1 g of sodium chloride under standard conditions of temperature and pressure -

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Stoichiometric Calculations

Chlorine gas ...

Question

Chlorine gas can be produced by reacting sulphuric acid with a mixture of $M n O_{2}$ and NaCl.
The reaction follows the equation;
$2 N a C l + M n O_{2} + 3 H_{2} S O_{4} \to 2 N a H S O_{4} + M n S O_{4} + C l_{2} + 2 H_{2} O$
What volume of chlorine can be produced from 1 g of sodium chloride under standard conditions of temperature and pressure ?

0.1915 L

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

19.15 L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20.22 L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.191 L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 0.1915 L
Volume of chlorine produce from 1 g of $N a C l$ under STP :

$∵$ 2 mole $N a C l$ (117 g) $\equiv$ 1 mole $C l_{2}$ (22.4 L at STP)

$∴$ 1 g $N a C l$ will give $\frac{22.4}{117}$ L $C l_{2}$ at STP

$= 0.191 L C l_{2}$ at STP

Suggest Corrections

Similar questions

Q. Chlorine gas is prepared by reaction of

H_{2} S O_{4}

with

M n O_{2}

and NaCl. What volume of

C l_{2}

will be produced at STP if 50 g of NaCl is taken in the reaction?

Q. Chlorine can be prepared by reacting MCI with

M n O_{2}

. The reaction is represented by the equation,

M n O_{2} (s) + 4 H C I (a q .) \to C l_{2} (g) + M n C l_{2} (a q .) + 2 H_{2} O (l)

Assuming that the reaction goes to completion, what mass of cone. HCI solution (36% HCI by mass) is needed to produce 2.5 g

C l_{2}

Q. Chlorine is prepared in the laboratory by treating manganese dioxide

(M n O_{2})

with aqueous hydrochloric acid according to the reaction,

M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O

How many grams of HCl will react with 5 g

M n O_{2}

Q. Aluminium reacts with chlorine gas to form aluminium chloride via the following reaction:

2 A l + 3 C l_{2} \to 2 A l C l_{3}

How many grams of aluminium chloride could be produced from 34 g of aluminium and 39 g of chlorine gas?

calculate the mass of $M n O_{2}$ , needed to produce 1.78 litres of chlorine gas at STP according to the equation
$M n O_{2}$ + 4HCl $\to$ $M n C l_{2}$ + 2 $H_{2} O$ + $C l_{2}$

[H = 1, Cl = 35.5, Mn = 54.9]

Join BYJU'S Learning Program

Chlorine gas can be produced by reacting sulphuric acid with a mixture of MnO2 and NaCl. The reaction follows the equation; 2NaCl+MnO2+3H2SO4→2NaHSO4+MnSO4+Cl2+2H2OWhat volume of chlorine can be produced from 1 g of sodium chloride under standard conditions of temperature and pressure ?

The correct option is B 0.1915 LVolume of chlorine produce from 1 g of NaCl under STP :∵ 2 mole NaCl (117 g) ≡ 1 mole Cl2 (22.4 L at STP) ∴ 1 g NaCl will give 22.4117 L Cl2 at STP=0.191 LCl2 at STP

The correct option is B 0.1915 L
Volume of chlorine produce from 1 g of $N a C l$ under STP :

$∵$ 2 mole $N a C l$ (117 g) $\equiv$ 1 mole $C l_{2}$ (22.4 L at STP)

$∴$ 1 g $N a C l$ will give $\frac{22.4}{117}$ L $C l_{2}$ at STP

$= 0.191 L C l_{2}$ at STP