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Standard XII

Chemistry

Reaction with Metals

Chlorine gas ...

Question

Chlorine gas is passed in a medium which has $p H = 12$ . Two products $A$ and $B$ are formed with water. Now $p H$ of medium is changed to $1$ by acidifying it. Again a product $C$ is formed with water. It is found that $A$ is strong oxidising agent.
Answer the following questions carefully: Oxidation of $C l$ in compound $B$ is:

- 1

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Solution

The correct option is C $- 1$
Option (A) is correct.
Lets take reaction of chlorine with hot solution of $N a O H$ as a medium which has higher $p H$ of 12.
$C l_{2} + N a O H \to N a C l O_{3} [A] + N a C l [B] + H_{2} O$
In [A], oxidation no. of $C l$ is +5.
In [B], oxidation no. of $C l$ is -1.

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Similar questions

Q. Chlorine gas is passed in a medium which has

p H = 12

. Two products

A

and

B

are formed with water. Now

p H

of medium is changed to

1

by acidifying it. Again a product

C

is formed with water. It is found that

A

is strong oxidising agent.

If the basic medium was of

K O H

, then which of the following statement is incorrect about compound

A

A hydrocarbon

(A)

has the molecular formula

(C_{8} H_{10})

. (A) is oxidized by a strong oxidizing agent to (B). (B) on dehydration and subsequent reaction with ammonia forms an imide, (C). (C) is then reacted with a strong inorganic base to form a compound that undergoes Hoffman bromamide reaction to give (D). (D) is treated with sodium nitrite in an ice cold acidic solution to form the product (E). (E) is a steam volatile compound and on nitration gives two mononitro derivatives. (E) is treated with sodium hydroxide to form the salt (F). On heating a solution of (F), bubble are formed due to release of gas. This gas does not burn. On analysis it was found that the gas has two components, one lighter than air and one heavier than air.

Compound

(B)

is :

Q. Mg burns in air to form two compound (A) and (B). (A) is sparingly soluble in water and the resulting solution is weakly basic. (B) dissolve in water to form (C) and gas (D) with dilute

H N O_{3}

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Question 59
A non-metal A, which is the largest constituent of air, when heated with $H_{2}$ in 1:3 ratio in the presence of catalyst $Fe$ , gives a gas B.
On heating with $O_{2}$ , it gives an oxide C. If this oxide is passed into water in the presence of air it gives an acid D, which acts as a strong oxidising agent.

(a) Identify A, B, C and D
(b) To which group of periodic table does this non-metal belong?

Q. A solution of

K M n O_{4}

is reduced to various products depending upon its pH. At pH < 7 it is reduced to a colourless solution (A), at pH = 7 it forms a brown precipitate (B) and at pH > 7 it gives a green solution (C).
(A), (B) and (C) are :

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The correct option is C −1Option (A) is correct.Lets take reaction of chlorine with hot solution of NaOH as a medium which has higher pH of 12.Cl2+NaOH→NaClO3[A]+NaCl[B]+H2OIn [A], oxidation no. of Cl is +5.In [B], oxidation no. of Cl is -1.

The correct option is C $- 1$
Option (A) is correct.
Lets take reaction of chlorine with hot solution of $N a O H$ as a medium which has higher $p H$ of 12.
$C l_{2} + N a O H \to N a C l O_{3} [A] + N a C l [B] + H_{2} O$
In [A], oxidation no. of $C l$ is +5.
In [B], oxidation no. of $C l$ is -1.