Question

Chlorine gas is passed in a medium which has $pH=12$. Two products $A$ and $B$ are formed with water. Now $pH$ of medium is changed to $1$ by acidifying it. Again a product $C$ is formed with water. It is found that $A$ is strong oxidising agent.

If the basic medium was of $KOH$, then which of the following statement is incorrect about compound $A$?

• A. Compound $A$ is used in fireworks
• B. Compound $A$ is used in safety matches
• C. Compound $A$ is strong oxidising agent
• D. Compound $A$ is $KCl{O}_2$

Answer 1

The correct option is D Compound $A$ is $KCl{O}_2$

Option (D) is correct.

Compound A is $KCl{O}_3$.

$C{l}_2+KOH⟶KCl{O}_3\left[A\right]+KCl\left[B\right]+H_{2}O$