Chlorine gas is passed into a solution containing KF, KI and KBr and CHCl $_{3}$ is added. The initial colour in CHCI $_{3}$ layer is:

violet due to formation of I

_{2}

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orange due to formation of Br

_{2}

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colourless due to formation of F

_{2}

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no colour change due to no reaction

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Solution

The correct option is B violet due to formation of I $_{2}$
From the figure, it can be seen that the reduction potential of iodide is lowest.

$C l_{2} + 2 K I \to 2 K C l + l_{2}$

This liberated iodine will react with $C H C I_{3}$ layer and forms a violet layer.

Hence, option A is correct.

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