Chlorine has two naturally occurring isotopes, 35Cl and 37Cl. If the atomic mass of Cl is 35.45, the ratio of natural abundance of 35Cl and 37Cl is closest to:
A
3.5:1
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B
3:1
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C
2.5:1
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D
4:1
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Solution
The correct option is B3:1 The percent abundance of Cl−35 and Cl−37 is equal to 100.
Let abundance of 35Cl=xand abundance of 37Cl=100−x.
As we know,
Atomic weight of 35Cl= 34.9689
Atomic weight of 37Cl= 36.9695
Atomic mass of Cl= 35.45
Average atomic mass = 34.9689(x)+36.9695(100−x)100=35.45
x=76%
Abundance of Cl−35 = 76%
Abundance of Cl−37 = 24%
Hence, the ratio of their natural abundance is approximately equal to 3:1.