Chlorine is evolved by the action of:

H_{2} {S O}_{4} o n N a C l

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H C l o n K_{2} {S O}_{4}

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H C l o n K M N O_{4}

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H N O_{3} o n K C l

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Solution

The correct option is C $H C l o n K M N O_{4}$
Option $(C)$ is the correct answer.
$C h l o r i n e$ is evolved by the action of $H C l$ on $K M n O_{4}$
$2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 8 H_{2} O + 5 C l_{2}$

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