Question

Chlorine on reaction with hot and concentrated sodium hydroxide gives $X+Y+H_{2}O$ whereas chlorine on reaction with cold and dilute sodium hydroxide gives $X+Z+H_{2}O$. Compound $X$ is:

• A. $NaOC{l}_3$
• B. $NaOCl$
• C. $NaCl$
• D. $N_2$

Answer 1

The correct option is C $NaCl$

With cold and dilute alkalies chlorine produces a mixture of chloride and hypochlorite but with hot and concentrated alkalies it gives chloride and chlorate.
$\underset{\text{Hot and concentrated}}{6NaOH}+3C{l}_2\to \underset{X}{5NaCl}+\underset{Y}{NaCl{O}_3}+3H_{2}O$
$\underset{\text{Cold and dilute}}{2NaOH}+C{l}_2\to \underset{X}{NaCl}+\underset{Z}{NaOCl}+H_{2}O$
Hence, compound $X$ is $NaCl$.