Chlorine reacts with excess of ammonia to form :

N H_{4} C l

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N_{2} + H C l

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N_{2} + N H_{4} C l

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N_{2} + N C l_{3}

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Solution

The correct option is C $N_{2} + N H_{4} C l$
It reacts with ammonia under two conditions.
When ammonia in excess
$8 N H_{3} + 3 C l_{2} \to N_{2} + 6 N H_{4} C l$
When chlorine in excess
$N H_{3} + 3 C l_{2} \to N C l_{3} + 3 H C l$

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