Chlorine reacts with hot and concentrated $N a O H$ and produces compounds (X) and (Y). Compound (X) gives white precipitate with silver nitrate solution. The average bond order between $C l$ and $O$ atoms in (Y) is t; find 3t.

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Solution

$3 C l_{2} + 6 N a O H C o n c . ⟶ 5 N a C l + N a C l O_{3} + 3 H_{2} O$
$A g^{+}$ forms precipitate with $C l^{-}$ i.e. $A g C l$ .
$A g C l O_{3}$ is soluble.
$∴$ X is $N a C l$
Y is $N a C l O_{3}$
Now, structure of $C l O_{3}^{-}$ is

$∴$ Bond order is $\frac{5}{3} \Rightarrow t = \frac{5}{3}$
$3 t = 5$

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Chlorine reacts with hot and concentrated NaOH and produces compounds (X) and (Y). Compound (X) gives white precipitate with silver nitrate solution. The average bond order between Cl and O atoms in (Y) is t; find 3t.

3Cl2+6NaOHConc.⟶5NaCl+NaClO3+3H2O Ag+ forms precipitate with Cl– i.e. AgCl. AgClO3 is soluble. ∴ X is NaCl Y is NaClO3 Now, structure of ClO−3 is ∴ Bond order is 53⇒t=53 3t=5

Chlorine reacts with hot and concentrated $N a O H$ and produces compounds (X) and (Y). Compound (X) gives white precipitate with silver nitrate solution. The average bond order between $C l$ and $O$ atoms in (Y) is t; find 3t.