Question

Chlorine reacts with $NaOH$ under various conditions to give :

• A. $NaCl$
• B. $NaOCl$
• C. $NaCl{O}_3$
• D. All the above

Answer 1

The correct option is D All the above

$\underset{\left(dil\right)}{2NaOH}+C{l}_2\stackrel{Cold}{\to }NaCl+\underset{Sod.hypochlorite}{NaClO+H_{2}O}$

$\underset{\left(conc\right).}{6NaOH}+3C{l}_2\stackrel{hot}{\to }5NaCl+\underset{Sodiumchlorate}{NaCl{O}_3+3H_{2}O}$

So all are formed,

Option D is correct.