Chlorine, Y and Iodine form a Dobereiner's triad. Identify the atomic weight of Y.

162.5

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81.25

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121.5

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90.5

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Solution

The correct option is D 81.25
According to Dobereiner, the atomic weight of the central element of the triad is the arithmetic mean of the atomic weights of the other two members.Atomic weight of Cl = 35.5 and Iodine is 126.9.Therefore atomic weight of Y = $\frac{35.5 + 126.9}{2}$ = 81.2

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Chlorine, Y and Iodine form a Dobereiner's triad. Identify the atomic weight of Y.

The correct option is D 81.25According to Dobereiner, the atomic weight of the central element of the triad is the arithmetic mean of the atomic weights of the other two members.Atomic weight of Cl = 35.5 and Iodine is 126.9.Therefore atomic weight of Y = 35.5+126.92 = 81.2

The correct option is D 81.25
According to Dobereiner, the atomic weight of the central element of the triad is the arithmetic mean of the atomic weights of the other two members.Atomic weight of Cl = 35.5 and Iodine is 126.9.Therefore atomic weight of Y = $\frac{35.5 + 126.9}{2}$ = 81.2