Question

Chloroform is ($CHC{l}_3$):

• A. primary alkyl halide
• B. secondary alkyl halide
• C. teriary alkyl halide
• D. None of these

Answer 1

Answer: (D)

None of these

$\begin{array}{c}\text{The degree of alkyl halide is decided by the number}\\ \text{of carbon atoms attached to carbon containing halide}\\ \text{since, there are no other carbons, its degree is}0\\ \text{Hence,}D\text{is correct.}\end{array}$