Question

Chlorophyll present in green leaves of plants absorbs light at $4.620\times {10}^{14}Hz$. Which part of the electromagnetic spectrum does it belong to ?

• A. UV
• B. IR
• C. Far IR
• D. Visible

Answer 1

Answer: (D)

Visible

$\lambda =\frac{c}{v}=\frac{3.0\times {10}^{8}m{s}^{-1}}{4.620\times {10}^{14}Hz}$
$=0.6494\times {10}^{-6}m$
$=649.4nm$;
Thus, it belongs to visible region