Question

Choose correct option according to increasing order of covalent character:-

• A. NaCl<CaCl₂<SnCl₂<SnCl₄
• B. CaCl₂<SnCl₂<SnCl₄<NaCl
• C. SnCl₂<SnCl₄<CaCl₂ <NaCl
• D. SnCl₄ <SnCl₂ <CaCl₂ <NaCl

Answer 1

The correct option is A NaCl<CaCl₂<SnCl₂<SnCl₄

$NaCl\&CaC{l}_2$ are ionic compounds and $SnC{l}_4$ with Sn(+4) oxidation state is more covalent than $SnC{l}_2$ with Sn(+2) oxidation state due to Fajan's rule of polarization which states that smaller cationic size leads to more polarizing power and thus more covalent character of the bond.