Choose number-letter group which is different from the others.

R V 3

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D G 2

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E K 5

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J R 6

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P Y 8

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Solution

The correct option is D $J R 6$
Putting A = 1, B = 2, ......, Z = 26, we have :
RV3 = V - (R + 3) = 22 - (18 + 3 ) = 1.
DG2 = G - (D + 2) = 7 - (4 + 2 ) = 1;
EK5 = K - (E + 5) = 11 - (5 + 5) = 1;
JR6 = R - (J + 6) = 18 - (10 + 6) = 2;
PY8 = Y - (P + 8) = 25 - (16 + 8) = 1;
Hence, the odd one is option D.

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