Choose the correct answer form alternatives given.
Two pipes A and B can fill a water tank in 20 and 24 minutes respectively and a third pipe C, can empty at the rate of 3 gallons per minute. If A, B and C opened together they fill the tank in 15 minutes. The capacity (in gallons) of the tank is.?

120

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150

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180

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Solution

The correct option is A 120
Let the capacity of tank be $120$ units. [LCM of 20,24& 15]
A does = $\frac{120}{20} = 6$ units / minute.
B does = $\frac{120}{24} = 5$ units / minute.
A and B together fIll $6 + 5 = 11$ units/minute
When the leakage pipe C is opened,
$\frac{120}{15}$ = 8 units of the tank is filled per minute
Hence, pipe C empties 3 units/minute
So, if pipe C alone is opened, the tank is emptied in $\frac{120}{3}$ =40 minutes
Also, pipe C comes out 3 gallons/minute.
Hence, the total capacity of the tank 40 $\times$ 3 = $120$ gallons

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Choose the correct answer form alternatives given.Two pipes A and B can fill a water tank in 20 and 24 minutes respectively and a third pipe C, can empty at the rate of 3 gallons per minute. If A, B and C opened together they fill the tank in 15 minutes. The capacity (in gallons) of the tank is.?

Choose the correct answer form alternatives given.
Two pipes A and B can fill a water tank in 20 and 24 minutes respectively and a third pipe C, can empty at the rate of 3 gallons per minute. If A, B and C opened together they fill the tank in 15 minutes. The capacity (in gallons) of the tank is.?