Choose the correct answer form the alternatives given. E∘ for Cl2/Cl−=+1.36,I2/I−=+0.53,Ag+/Ag=+0.79,Na+/Na=−2.71 and Li+/Li=−3.04V What is the order of decreasing reducing strength for these species?
A
Li>Cl−>Ag>I−>Na
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B
Li>Na>I−>Ag>Cl−
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C
Cl−>Ag>I−>Na>Li
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D
Na>Li>Ag>Cl−>I−
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Solution
The correct option is BLi>Na>I−>Ag>Cl− more negative the E∘value stronger will be the reducing strength. Thus the decreasing order of reducing strength is Li>Na>I−>Ag>Cl−