Choose the Correct answer from alternative given-Light from two coherent sources of the same amplitude A and wavelength - illuminates the screen- The intensity of the central maxima is I0 - If the sources were incoherent- the intensity at the same point will be then-

The correct option is D I_02 If sources are coherent I_R=I_1+I_2+2√(I_1I_2)cosϕ I_0=I+I+2Icos0^o=4I If sources are incoherent, I_R=I_1+I_2= ...

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Standard XII

Physics

Intensity Explanation in YDSE

Choose the Co...

Question

Choose the Correct answer from alternative given.
Light from two coherent sources of the same amplitude A and wavelength $λ$ illuminates the screen. The intensity of the central maxima is $I_{0}$ . If the sources were incoherent, the intensity at the same point will be then:

4 I_{0}

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2 I_{0}

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I_{0}

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\frac{I_{0}}{2}

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Solution

The correct option is D $\frac{I_{0}}{2}$
If sources are coherent $I_{R} = I_{1} + I_{2} + 2 \sqrt{I_{1} I_{2}} c o s ϕ$
$I_{0} = I + I + 2 I c o s 0^{o} = 4 I$
If sources are incoherent, $I_{R} = I_{1} + I_{2} = 2 I = \frac{4 I_{0}}{2} = \frac{I_{0}}{2}$

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Choose the Correct answer from alternative given.Light from two coherent sources of the same amplitude A and wavelength λ illuminates the screen. The intensity of the central maxima is I0 . If the sources were incoherent, the intensity at the same point will be then:

The correct option is D I02If sources are coherent IR=I1+I2+2√I1I2cosϕI0=I+I+2Icos0o=4IIf sources are incoherent, IR=I1+I2=2I=4I02=I02

Choose the Correct answer from alternative given.
Light from two coherent sources of the same amplitude A and wavelength $λ$ illuminates the screen. The intensity of the central maxima is $I_{0}$ . If the sources were incoherent, the intensity at the same point will be then:

The correct option is D $\frac{I_{0}}{2}$
If sources are coherent $I_{R} = I_{1} + I_{2} + 2 \sqrt{I_{1} I_{2}} c o s ϕ$
$I_{0} = I + I + 2 I c o s 0^{o} = 4 I$
If sources are incoherent, $I_{R} = I_{1} + I_{2} = 2 I = \frac{4 I_{0}}{2} = \frac{I_{0}}{2}$