Question

Choose the correct answer from the alternative given.
Area of triangle formed by straight lines $x-y=0,x+y=0$ and $2x=5$ is

• A. $25$
• B. $\frac{25}{2}$
• C. $\frac{25}{4}$
• D. None of these

Answer 1

Answer: (C)

$\frac{25}{4}$

Given:

$L_1:x-y=0$..................$\left(1\right)$

$L_2:x+y=0$..................$\left(2\right)$

$L_3:2x=5$.....................$\left(3\right)$ forms a triangle having vertices $A,B,C$.

From the diagram we can see that the height of triangle $ABC$ is $AD=\frac{5}{2}$ units and base $BC=5$ units.

So, area of triangle $ABC=\frac{1}{2}\times \left(base\right)\times \left(height\right)=\frac{1}{2}\left(\frac{5}{2}\right)\left(5\right)=\frac{25}{4}$.