Choose the correct answer from the alternative given.
When an oxide of manganese (P) is fused with KOH in the presence of an oxidizing agent and dissolved in water, it gives a dark green solution of compound (Q). Compound (Q) disproportionates in neutral or acidic solution to give purple compound (R). An alkaline solution of compound (R) oxidizes potassium iodide solution to a compound (S) and compound (P) is also formed. Compounds P to S are:

(P) - M n O_{4}^{-}, (Q) - K I O_{3}, (R) - M n O_{2}, (S) - K_{2} M n O_{4}

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(P) - M n O_{2}, (Q) - K_{2} M n O_{4}, (R) - M n O_{4}^{-}, (S) - K I O_{3}

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(P) - M n O_{2}, (Q) - M n O_{4}^{-}, (R) - K 2 M n O_{4}, (S) - K I O_{3}

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(P) - K_{2} M n O_{4}, (Q) - M n O_{2}, (R) - M n O_{4}^{-}, (S) - K I O_{3}

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Solution

The correct option is B $(P) - M n O_{2}, (Q) - K_{2} M n O_{4}, (R) - M n O_{4}^{-}, (S) - K I O_{3}$
Oxide of manganese $- P - {M n O}_{2}$
$2 {M n O}_{2} + 4 K O H + O_{2} \to 2 K_{2} {M n O}_{4} + 2 H_{2} O$
$↓$ $↓$
oxidizing dark green solution
agent $(Q) - K_{2} {M n O}_{4}$
$K_{2} {M n O}_{4} + H^{+} \to {K M n O}_{4} + {M n O}_{2} + H_{2} O + K^{+}$
$↓$
purpule compound (R)
$[{M n O}_{4}^{-}]$ $(S) - {K I O}_{3}$

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Similar questions

$M n O_{2}$ when fused with KOH and oxidized in air gives a dark green compound X. In acidic X. In acidic solution, X undergoes disproportion to give an intense purple compound Y and $M n O_{2}$ . The compounds X and Y respectively, are

Q. When

M n O_{2}

is fused with

K O H

in the presence of

K N O_{3}

as an oxidizing agent, it gives a dark green compound (A).
Compound (A) disproportionates in acidic solution to give purple compound (B).
An alkaline solution of compound (B) oxidises

K I

to compound (C) whereas an acidified solution of compound (B) oxidises

K I

to (D). Identify (A), (B), (C), and (D).

M n O_{2}

when fused with KOH and oxidized in air gives a dark green compound X. In acidic X. In acidic solution, X undergoes disproportion to give an intense purple compound Y and

M n O_{2}

. The compounds X and Y. respectively, are

Q. A violet compound of manganese (F) decomposes on heating to liberate oxygen and compounds (Q) and (R) of manganese is formed. Compound (R) reacts with KOH in the presence of potassium nitrate to give compound (Q). On heating compound (R) with conc.

H_{2} S O_{4}

and NaCl, chlorine gas is liberated and a compound (S) of manganese along with other products is formed. Compounds P to S are:

Find out the correct order of reactivity of the given compounds with respect to

S_{N} 2

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The correct option is B (P)−MnO2,(Q)−K2MnO4,(R)−MnO−4,(S)−KIO3Oxide of manganese −P−MnO22MnO2+4KOH+O2→2K2MnO4+2H2O ↓ ↓ oxidizing dark green solution agent (Q)−K2MnO4K2MnO4+H+→KMnO4+MnO2+H2O+K+ ↓ purpule compound (R) [MnO−4] (S)−KIO3