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Question

Choose the correct answer from the alternatives given.
Assume a bulb of efficiency 2.5% as a point source. The peak values of electric and magnetic fields produced by the radiation coming from a 100 W bulb at a distance of 3 m is respectively

A
2.5Vm1,3.6×108T
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B
4.2Vm1,2.8×108T
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C
4.08Vm1,1.36×108T
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D
3.6Vm1,3.6×108T
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Solution

The correct option is D 4.08Vm1,1.36×108T
Here intensity, I=powerarea

= 100×2.54π(3)2×100=2.536πWm2

Half of this intensity belongs to electronic field and half of that to magnetic field.

I2=14ε0E20c

or
Eo=2Iϵ0c    2×2.536π14π×9×109×3×1084.08Vmi

Bo=E0c=4.083×108=1.36×108T

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