Choose the correct answer from the alternatives given. Assume a bulb of efficiency 2.5% as a point source. The peak values of electric and magnetic fields produced by the radiation coming from a 100 W bulb at a distance of 3 m is respectively
A
2.5Vm1,3.6×10−8T
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B
4.2Vm1,2.8×10−8T
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C
4.08Vm1,1.36×10−8T
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D
3.6Vm1,3.6×10−8T
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Solution
The correct option is D4.08Vm1,1.36×10−8T
Here intensity, I=powerarea
= 100×2.54π(3)2×100=2.536πWm−2
Half of this intensity belongs to electronic field and half of that to magnetic field.