The correct option is A 65/144
$\displaystyle\, \frac{Sec \theta + Tan \theta}{Sec \theta Tan \theta} = 2 - \frac{51}{79}$
$\displaystyle\, \frac{Sec \theta + Tan \theta}{Sec \theta Tan \theta} = \frac{209}{79}$
Applying Componendo and Dividendo,
Secθ+Tanθ+SecθTanθSecθTanθ[secθ+Tanθ]=209+7920979
$\displaystyle\, \frac{2 sec \theta}{2 Tan \theta} = \frac{288}{130}$
$\displaystyle\, \frac{sec \theta }{Tan \theta} = \frac{288}{130}$
1Sinθ=288130⇒Sinθ=65144