Choose the correct answer from the alternatives given.
In the $C_{4}$ pathway the molecule that combines with carbon dioxide is

glyceraldehyde phosphate

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ribulose biphosphate

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phosphoenol pyruvic acid

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citric acid

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Solution

The correct option is C phosphoenol pyruvic acid
The C $_{4}$ (or Hatch-Slack) pathway the carbon dioxide combines first with phosphoenolpyruvic acid (PEP) to form a four-carbon molecule, Oxaloacetatic acid.
Thus, the correct answer is 'Phosphoenol pyruvic acid.'

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