Choose the correct answer from the alternatives given-Poynting vectors S- is defined as S- 1-0E-B- the average value of -S-over a single period -T-is given by

The correct option is B E_0^2/2cμ_o Poynting vector is given by, S⃗=E⃗×B⃗ #956;_0 Average value of magnitude of radiant flux density over one cycle ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Theorems for Continuity

Choose the co...

Question

Choose the correct answer from the alternatives given.
Poynting vectors $\to S$ is defined as $\to S = \frac{1}{μ_{0}} \to E \times \to B$ . the average value of $^{'}^{'}$ over a single period 'T'is given by

E_{0}^{2} / 2 c μ_{o}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

E_{0}^{2} / c μ_{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 E_{0}^{2} / c μ_{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

E_{0}^{2} / c μ_{o}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $E_{0}^{2} / 2 c μ_{o}$
Poynting vector is given by, $\to S = \frac{\to E \times \to B}{μ_{0}}$

Average value of magnitude of radiant flux density over one cycle is
$S_{a v} = \frac{1}{μ_{0}} ∣_{0} \times_{0} | (\frac{1}{T}) \int_{0}^{T} c o s^{2} (k x - ω t) d t$

$[∵ E = E_{0} c o s (k x - ω t), B = B_{0} c o s (k x - ω t)]$

$= \frac{E_{0} B_{0}}{μ_{0}} (\frac{1}{T}) (\frac{T}{2})$

$= \frac{E_{0} B_{0}}{2 μ_{0}}$ $[∵ \int_{0}^{T} c o s^{2} (k x - ω t) d t = \frac{T}{2}]$

$S_{a v} = \frac{E_{0} (E_{0} / c)}{2 μ 0} = (\frac{1}{2 c μ_{0}}) E_{0}^{2} (∵ B_{0} = \frac{E_{0}}{c})$

So, option $(A)$ is correct

Suggest Corrections

Similar questions

Q. If the two adjacent sides of two rectangles are represented by the vectors

\to p = 5 \to a - 3 \to b; \to q = - \to a - 2 \to b

and

\to r = - 4 \to a - \to b; \to s = - \to a + \to b

respectively, then the angle between the vectors

\to x = \frac{1}{3} (\to p + \to r + \to s)

and

\to y = \frac{1}{5} (\to r + \to s)

Q. If

\to p = 3 \to a - 5 \to b; \to q = 2 \to a + \to b; \to r = \to a + 4 \to b; \to s = - \to a + \to b

are four vectors such that

sin (\to p \land \to q) = 1

and

sin (\to r \land \to s) = 1

then

cos (\to a \land \to b)

is :

Q. The value of

\cdot 8642 E 02 \div \cdot 2562 E 02.

is?

Q. If

\int \to E . \to d s = 0

over a closed surface, then:

Q. Poynting vectors

\to S

is defined as

\to S = \frac{1}{μ_{0}} \to E \times \to B

. The average value of

\to S

over a single period T is given by

Join BYJU'S Learning Program

Choose the correct answer from the alternatives given.Poynting vectors →S is defined as →S=1μ0→E×→B. the average value of ′→S′over a single period 'T'is given by

Choose the correct answer from the alternatives given.
Poynting vectors $\to S$ is defined as $\to S = \frac{1}{μ_{0}} \to E \times \to B$ . the average value of $^{'}^{'}$ over a single period 'T'is given by