Question

Choose the correct answer from the alternatives given.
Radiations of intensity $0.5W/m^2$ are striking a metal plate. The pressure on the plate is then

• A. $0.166\times {10}^{-8}N{m}^{-2}$
• B. $0.332\times {10}^{-8}N{m}^{-2}$
• C. $0.111\times {10}^{-8}N{m}^{-2}$
• D. $0.083\times {10}^{-8}N{m}^{-2}$

Answer 1

The correct option is A $0.166\times {10}^{-8}N{m}^{-2}$

Given: The intensity of the incident radiations is $0.5W/m^2$.

To find: The radiation pressure on the plate.

The radiation pressure experienced by the plate is given as;

$P=\frac{I}{c}\Rightarrow \frac{0.5}{3\times {10}^8}\Rightarrow 0.166\times {10}^{-8}N{m}^{-2}$

Option $\left(A\right)$ is correct.