Choose the correct answer from the alternatives given.
The largest among the numbers $(0.1)^{2}, \sqrt{0.0121}, 0.12 a n d \sqrt{0.0004}$ is

(0.1)^{2}

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\sqrt{0.0121}

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0.12

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\sqrt{0.0004}

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Solution

The correct option is C $0.12$
We have
$(0.1)^{2} = 0.01.$
$\sqrt{0.0121}$ $= 0.11$ ,
$0.12$ .
$\sqrt{00004}$ $= 0. 02$
The largest among them is 0.12.

Suggest Corrections

Similar questions

\frac{0.008 \times 0.01 \times 0.0072}{(0.12 \times 0.0004)}

\frac{(0.0104 - 0.002) + 0.366 \times 0.002}{0.12 \times 0.12}

(\frac{0.12 \times (0.0104 - 0.002) + 0.36 \times 0.002) \times 100}{0.12 \times 0.12}

Simplify :

0.12×(0.0104-0.002)+0.36×0.002

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