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Standard IX

Mathematics

Zeroes of a Polynomial

Choose the co...

Question

Choose the correct answer from the alternatives given :
When the polynomial $(6 x^{4} + 8 x^{3} + 17 x^{2} + 21 x + 7)$ is divided by $(3 x^{2} + 4 x + 1)$ , the remainder is (ax + b). Therefore,

a =

1

, b =

2

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a =

1

, b =

- 2

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a =

2

, b =

1

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a =

- 1

, b =

- 2

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Solution

The correct option is A a = $1$ , b = $2$

According to the question,
x + 2 = ax + b
a = 1 & b = +2

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Similar questions

Q. If the polynomial

6 x^{4} + 8 x^{3} + 17 x^{2} + 21 x + 7

is divided by another polynomial

3 x^{2} + 4 x + 1

, the remainder comes out to be

a x + b

, find a and b.
[4 MARKS]

Q. If the polynomial

f (x) = (6 x^{4} + 8 x^{2} + 17 x^{2} + 21 x + 7)

is divided by another polynomial

g (x) = 3 x^{2} + 4 x + 1

the remainder is

(a x + b)

. Find

a

and

b

Q. When the polynomial

x^{4} + x^{2} + 1

is divided by

(x + 1) (x^{2} - x + 1)

then the remainder is

a x + b

, then

a + b

is equal to

Q. The polynomial f(x) = x⁴ − 2x³ + 3x² − ax = b when divided by (x − 1) and (x + 1) leaves the remainder 5 and 19 respectively. Find the values of a and b. Hence, find the remainder when f(x) is divided by (x − 2).

The polynomial $p (x) = x^{4} - 2 x^{3} + 3 x^{2} - a x + b$ when divided by (x-1) and (x +1) leaves the remainders 5 and 19 respectively. Find the values of a and b. Hence, find the remainder when p(x) is divided by (x -2).

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Choose the correct answer from the alternatives given :When the polynomial (6x4+8x3+17x2+21x+7) is divided by (3x2+4x+1) , the remainder is (ax + b). Therefore,

The correct option is A a = 1, b = 2According to the question,x + 2 = ax + ba = 1 & b = +2

Choose the correct answer from the alternatives given :
When the polynomial $(6 x^{4} + 8 x^{3} + 17 x^{2} + 21 x + 7)$ is divided by $(3 x^{2} + 4 x + 1)$ , the remainder is (ax + b). Therefore,

The correct option is A a = $1$ , b = $2$

According to the question,
x + 2 = ax + b
a = 1 & b = +2