Question

Choose the correct answer from the options given below.

The salt solution which does not react with Ammonium hydroxide

• A. Calcium nitrate
• B. Zinc nitrate
• C. Lead nitrate
• D. Copper nitrate

Answer 1

The correct option is A

Calcium nitrate

Part 1:- Explanation for correct answer:-

Option (A) Calcium nitrate

1. There is no reaction or precipitation when Ammonium hydroxide is introduced to Calcium nitrate.
2. An excessive amount of Ammonium hydroxide has no effect.
3. Ammonium hydroxide is a weak acid, the ${\mathrm{OH}}^{-}$ ions become difficult to displace the ${{\mathrm{NO}}_3}^{2-}$ ions in Calcium nitrate.
4. Hence the option is correct.

Part 2:- Explanation for incorrect answers:-

Option (B) Zinc nitrate

1. A white, gelatinous precipitate is generated when Ammonium hydroxide is introduced to Zinc nitrate. In the presence of too much Ammonium hydroxide, this precipitate dissolves.
2. $\underset{\mathrm{Zinc}\mathrm{nitrate}}{\mathrm{Zn}{\left({\mathrm{NO}}_3\right)}_2\left(\mathrm{aq}\right)}+\underset{\mathrm{Ammonium}\mathrm{hydroxide}}{2{\mathrm{NH}}_4\mathrm{OH}\left(\mathrm{aq}\right)}\to \underset{\mathrm{Zinc}\mathrm{hydroxide}}{\mathrm{Zn}{\left(\mathrm{OH}\right)}_2\left(\mathrm{s}\right)(\downarrow )}+\underset{\mathrm{Ammonium}\mathrm{nitrate}}{2{\mathrm{NH}}_4{\mathrm{NO}}_3\left(\mathrm{aq}\right)}$
3. Hence the option is incorrect.

Option (C) Lead nitrate

1. A chalky white precipitate is formed when Ammonium hydroxide is introduced to Lead nitrate. In the presence of too much Ammonium hydroxide, the precipitate does not dissolve.
2. $\underset{\mathrm{Lead}\mathrm{nitrate}}{\mathrm{Pb}{\left({\mathrm{NO}}_3\right)}_2\left(\mathrm{aq}\right)}+\underset{\mathrm{Ammonium}\mathrm{hydroxide}}{2{\mathrm{NH}}_4\mathrm{OH}\left(\mathrm{aq}\right)}\to \underset{\mathrm{Lead}\mathrm{hydroxide}}{\mathrm{Pb}{\left(\mathrm{OH}\right)}_2\left(\mathrm{s}\right)(\downarrow )}+\underset{\mathrm{Ammonium}\mathrm{nitrate}}{2{\mathrm{NH}}_4{\mathrm{NO}}_3\left(\mathrm{aq}\right)}$
3. Hence the option is incorrect.

Option (D) Copper nitrate

1. A pale blue precipitate is formed when Ammonium hydroxide is introduced to Copper nitrate. Excess Ammonium hydroxide will result in a dark, inky blue solution.
2. $\underset{\mathrm{Copper}\mathrm{nitrate}}{\mathrm{Cu}{\left({\mathrm{NO}}_3\right)}_2\left(\mathrm{aq}\right)}+\underset{\mathrm{Ammonium}\mathrm{hydroxide}}{2{\mathrm{NH}}_4\mathrm{OH}\left(\mathrm{aq}\right)}\to \underset{\mathrm{Copper}\mathrm{hydroxide}}{\mathrm{Cu}{\left(\mathrm{OH}\right)}_2\left(\mathrm{s}\right)(\downarrow )(\mathrm{pale}\mathrm{blue})}+\underset{\mathrm{Ammonium}\mathrm{nitrate}}{2{\mathrm{NH}}_4{\mathrm{NO}}_3\left(\mathrm{aq}\right)}$
3. Hence the option is incorrect.

Therefore, option (A) Calcium nitrate does not react with Ammonium hydroxide.