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Arrhenius Acid

Choose the co...

Question

Choose the correct answer.
$H_{3} O^{+} (a q) + O H^{-} (a q) \to$

2 H_{2} O (l)

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2 H_{2} O (s)

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2 H_{2} O (g)

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H_{2} O (l)

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Solution

The correct option is A $2 H_{2} O (l)$
This is referred to as the net ionic equation for the neutralization reaction in which hydronium ion accepts $O H^{-}$ ion to form the water molecule.
$H_{3} O^{+} (a q) + O H^{-} (a q) \to 2 H_{2} O (l)$

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Similar questions

H_{2} O_{(l)} + H_{2} O_{(l)} ⇌ H_{3} O_{(a q)}^{+} + O H_{(a q)}^{-}

H_{2} C_{2} O_{4} (a q) + H_{2} O (l) ⇌ H_{3} O + (a q) + H C_{2} O_{4}^{-} (a q)

H C_{2} O_{4}^{-} (a q) + H_{2} O (l) ⇌ H_{3} O + (a q) + C_{2} O_{4}^{2 -} (a q)

K_{c 1} = 5.9 \times 10^{- 2}

K_{c 2} = 6.4 \times 10^{- 5}

25^{0} C

K_{c}

H_{2} C_{2} O_{4} (a q) + 2 H_{2} O (l) ⇌ 2 H_{3} O + (a q) + C_{2} O_{4}^{2 -} (a q)

H_{2} C_{2} O_{4} (a q) + H_{2} O (l) ⇌ H_{3} O + (a q) + H C_{2} O_{4} - (a q)

H C_{2} O_{5} - (a q) + H_{2} O (l) ⇌ H_{3} O + (a q) + C_{3} O_{4}^{2} - (a q)

K_{c l} = 5.9 \times 10^{- 2}

K_{c 2} = 6.4 \times 10^{- 5}

25^{\circ} C

K_{c}

(3)

H_{2} C_{2} O_{4} (a q) + 2 H_{2} O (l) ⇌ 2 H_{3} O + (a q) + C_{2} O_{4}^{2} - (a q)

H_{2} S O_{4} (a q) + H_{2} O (l) ⇌ H_{3} O^{+} (a q) + H S O_{4}^{-} (a q)

H C_{2} H_{3} O_{2} (a q) + H_{2} O (l) ⇌ H_{3} O^{+} (a q) + C_{2} H_{3} O_{2}^{-} (a q)

H_{2} S_{(g)} + {H_{2} O}_{(l)} ⇌ {H_{3} O}_{(a q)}^{+} + {H S^{-}}_{(a q)}

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