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Question

Choose the correct answer.
19x4x2dx equals to
(a)19sin1(9x88)+C(b)12sin1(8x99)+C(c)13sin1(9x88)+C(d)12sin1(9x89)+C

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Solution

19x4x2dx=14194xx2121[x294x+(98)2]+(98)2dx=121(98)2(x98)2dx=12sin1(x9898)+C[dxa2x2=sin1(xa)]=12sin1(8x99)+C
Hence, the option (b)is correct.


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