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Question
Choose the correct answer which satisfies the linear equations: x−y=−50 and x+y=10
Choose the correct answer which satisfies the linear equations: x−y=−50 and x+y=10
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Solution
The correct option is B (−20,30)
x−y=−50 ...... (1)
x+y=10 ...... (2)
Substitute the values of first option x=−20 and y=30 in equations 1 and 2
x−y=−50
−20−30=−50
−50=−50 which is true
x+y=10
−20+30=10
10=10 which is true
Therefore, the first option satisfied the linear equations.
Likewise substitute the value of second option x=20,y=−30
x−y=−50
20−(−30)=−50
50≠−50
x+y=10
20+(−30)=10
−10≠10
Similarly, x=−20,y=−30x−y=−50
−20−(−30)=−50
10≠−50
x+y=10
−20+(−30)=10
−50≠10Also, for x=−20,y=10x−y=−50
−20−10=−50
−30≠−50
x+y=10
−20+10=10
−10≠10
Here, the first option satisfied the linear equation.
Hence, the solution is (−20,30).
x−y=−50 ...... (1)
x+y=10 ...... (2)
Substitute the values of first option x=−20 and y=30 in equations 1 and 2
x−y=−50
−20−30=−50
−50=−50 which is true
x+y=10
−20+30=10
10=10 which is true
Therefore, the first option satisfied the linear equations.
Likewise substitute the value of second option x=20,y=−30
x−y=−50
20−(−30)=−50
50≠−50
x+y=10
20+(−30)=10
−10≠10
Similarly, x=−20,y=−30
x−y=−50
−20−(−30)=−50
10≠−50
x+y=10
−20+(−30)=10
−50≠10
−20−(−30)=−50
10≠−50
x+y=10
−20+(−30)=10
−50≠10
Also, for x=−20,y=10
x−y=−50
−20−10=−50
−30≠−50
x+y=10
−20+10=10
−10≠10
−20−10=−50
−30≠−50
x+y=10
−20+10=10
−10≠10
Here, the first option satisfied the linear equation.
Hence, the solution is (−20,30).
Hence, the solution is (−20,30).
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