Choose the correct answers from the alternatives given. Determine the order of genes along a chromosome based on the following recombination frequencies: AB, 8 map units; AC, 28 map units; AD, 25 map units; BC, 20 map units; BD, 33 map units
A
A-C-D-B
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B
C-D-B-A
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C
D-A-B-C
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D
B-A-C-D
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Solution
The correct option is C D-A-B-C If the sequence is D-A-B-C as shown below then, AB will have a distance of 8 map units, AC will have a distance of 8+20 (AB+BC), AD will have a distance of 25 map units, BC will have a distance of 20 map units and BD will have a distance of 25+8 (AD+AB)= 33 map units. This fulfills the given requirements,