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Question

Choose the correct answers from the alternatives given.
In ΔABC, the sides AB and AC are produced to P and Q respectively. The bisectors of PBCandQCB intersect at a point 0. then BOC is equal to:

A
90- 12A
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B
90+ 12A
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C
120 + 12A
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D
120 - 12A
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Solution

The correct option is A 90- 12A
2 1+B=180circ (linear pair)
1=9012B (1)
Similarly,
2=9012C (2)
BOC=180circ(1+2)
=180circ[180circ12 (B+C)]
=12[B+C]=12(180circA)=90circ12A

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