Choose the correct code of characteristics for the given order of hybrid orbitals of same atom, sp<sp2<sp3 (I) Electronegativity (II) Bond angle between same hybrid orbitals (III) Size (IV) Energy level
A
(II),(III),(IV)
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B
(III),(IV)
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C
(II),(IV)
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D
(I),(II),(III),(IV)
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Solution
The correct option is C(III),(IV) Given →Sp<Sp2<Sp3
electronegativity depends on S− character, more is the S− character, more is the electronegativity. So, the order for electronegativity should be Sp>Sp2>Sp3
bond angle between same hybrid orbitals is in the following order
Sp(180∘)>Sp2(120∘)>Sp3(109.5∘)
Size → more S−character→more compact→smaller size.
So, the given order is correct, Sp<Sp2<Sp3.
Energy level→since S−orbitals have lower energy closer than p− as they allow closer proximity of the e− to the nuclear. Thus, more p− character more energy. So, the order will be Sp<Sp2<Sp3