Choose the correct coefficients to completely balance the following reaction.
$a (N H_{4})_{3} P O_{4}$ + $b P b (N O_{3})_{4}$ $\to$ $c P b_{3} (P O_{4})_{4}$ + $d N H_{4} N O_{3}$

a=2, b=6, c=1, d=10

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a= 4, b=3, c=12, d=1

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a=3, b=4, c=1, d=12

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a=4, b=3, c=1, d=12

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Solution

The correct option is D a=4, b=3, c=1, d=12
Let's start with largest number of ions in the equation.
On RHS - No. of $P O_{4}^{3 -}$ ions = 4, hence a=4.
Now, on LHS no. of $N H_{4}^{+}$ ions = 12.
Therefore, d=12.
On LHS, $P b^{2 +}$ ions = 3, hence b=3. And lastly, c=1.

$4 (N H_{4})_{3} P O_{4}$ + $3 P b (N O_{3})_{4}$ $\to$ $P b_{3} (P O_{4})_{4}$ + $12 N H_{4} N O_{3}$

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Choose the correct coefficients to completely balance the following reaction. a(NH4)3PO4 + bPb(NO3)4 → cPb3(PO4)4 + dNH4NO3

The correct option is D a=4, b=3, c=1, d=12Let's start with largest number of ions in the equation. On RHS - No. of PO3−4 ions = 4, hence a=4. Now, on LHS no. of NH+4 ions = 12. Therefore, d=12. On LHS, Pb2+ ions = 3, hence b=3. And lastly, c=1. 4(NH4)3PO4+3Pb(NO3)4→Pb3(PO4)4+12NH4NO3

Choose the correct coefficients to completely balance the following reaction.
$a (N H_{4})_{3} P O_{4}$ + $b P b (N O_{3})_{4}$ $\to$ $c P b_{3} (P O_{4})_{4}$ + $d N H_{4} N O_{3}$