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B
6CO2+6H2O→C6H12O6+6O2
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C
C6H12O6+6H2O→6CO2+6O2H
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D
6CO2+6O2→C6H12O6+6H2O
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E
6CO2+C6H12O6→6O2+6H2O
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Solution
The correct option is B6CO2+6H2O→C6H12O6+6O2 Formation of one molecule of glucose (6C) requires 6 turns of Calvin cycle. Each turn includes splitting of one water molecule and release of one oxygen molecule. So, total six turns of Calvin cycle use six molecules of water and form one glucose molecule and six molecules of oxygen.