The correct option is B R−Cl<R−Br<R−I
In this reaction alkyl halide get reduced to alkane by cleavage of C−X.
CH3X+H2Zn, dil.HCl⟶RH+HX
As the size of the halogen increases down the group, the strength of C−X bond decreases. Also the stability of X− formed in the reaction is higher for I− due to its larger size. Thus, the reactivity of alkyl halide increases down the group. Therefore, the increasing order of reactivity of alkyl halides with zinc and dil. HCl is R−Cl<R−Br<R−I.
Hence, B is the correct answer.