Choose the correct matching of transition metal ion and magnetic moment from the codes given below. (Atomic number : $T i = 22, V = 23, F e = 26$ )
Transition element Magnetic moment (BM)
$(A)$ Titanium (III) $(1)$ $4.9$
$(B)$ Vanadium (II) $(2)$ $1.73$
$(C)$ Iron (II) $(3)$ $3.87$

(A) - (2), (B) - (3), (C) - (1)

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(A) - (2), (B) - (1), (C) - (3)

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(A) - (1), (B) - (2), (C) - (3)

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(A) - (1), (B) - (3), (C) - (2)

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(A) - (3), (B) - (2), (C) - (1)

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Solution

The correct option is A $(A) - (2), (B) - (3), (C) - (1)$

$∵$ Magnetic moment $(μ) = \sqrt{n (n + 2)}$ BM where, $n =$ number of unpaired electrons

$(A)$ Titanium $(I I I) \to 3 d^{1}$ , has one unpaired electron
$∴ μ = \sqrt{1 (1 + 2)} = \sqrt{3} = 1.73$ BM

$(B)$ Vanadium $(I I) \to 3 d^{3}$ , has $3$ unpaired electrons.
$∴ μ = \sqrt{3 (3 + 2)} = \sqrt{15} = 3.87$ BM

$(C)$ Iron $(I I) \to 3 d^{6}$ , has $4$ unpaired electrons.
$∴ μ = \sqrt{4 (4 + 2)} = \sqrt{24}$
$μ = 4.90$ BM

Therefore,
$(A) \to (2); (B) \to (3); (C) \to (1)$

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Transition element	Magnetic moment (BM)
$(A)$ Titanium (III)	$(1)$ $4.9$
$(B)$ Vanadium (II)	$(2)$ $1.73$
$(C)$ Iron (II)	$(3)$ $3.87$

Choose the correct matching of transition metal ion and magnetic moment from the codes given below. (Atomic number : Ti=22,V=23,Fe=26)Transition elementMagnetic moment (BM)(A) Titanium (III)(1) 4.9(B) Vanadium (II)(2) 1.73(C) Iron (II)(3) 3.87

Choose the correct matching of transition metal ion and magnetic moment from the codes given below. (Atomic number : $T i = 22, V = 23, F e = 26$ )
Transition element Magnetic moment (BM)
$(A)$ Titanium (III) $(1)$ $4.9$
$(B)$ Vanadium (II) $(2)$ $1.73$
$(C)$ Iron (II) $(3)$ $3.87$