Question

Choose the correct numbers of $\alpha$- and $\beta$-particles given out during nuclear transformation as :${}_{92}^{238}\text{U}{\to }_{82}^{214}\text{Pb}$

• A. Number of $\alpha$ particles = 6
• B. Number of $\alpha$ particles = 2
• C. Number of $\beta$ particles = 2
• D. Number of $\beta$ particles = 4

Answer 1

Answer: (A), (C)

Number of $\alpha$ particles = 6
Number of $\beta$ particles = 2

${}_{92}^{238}\text{U}{\to }_{82}^{214}\text{Pb}+m_2^4\text{He}+n_{-1}^{0}e$
$\therefore$ $\alpha$ =6 and $\beta$=2.

Total = 8