Choose the correct option:
(cosec θ+cot θ)×(1−cos θ)=
sin θ
cosec θ=1sin θ, cot θ=cos θsin θ
When we rationalise (1−cos θ), we get,
(1sin θ+cos θsin θ)×(1−cos θ)×(1+cos θ)(1+cos θ)=(1+cos θ)sin θ×(1−cos2θ)(1+cos θ).
After simplifying we get (1−cos2θ)sin θ. Now 1−cos2θ=sin2θ on further simplifying,
⇒sin2θsin θ=sin θ