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Hydrides of Nitrogen

Choose the co...

Question

Choose the correct option .

CsH > KH > NaH < LiH (Order of stability)

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H_{2} O < N H_{3} < C H_{4}

(Order of dipole moment)

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P H_{3} < A s H_{3} < N H_{3} < S b H_{3}

(Order of boiling point )

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X .................. H ___ X, X = O > F > N > S > Cl
(Order of strength of H-bonding)

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Solution

The correct option is C $P H_{3} < A s H_{3} < N H_{3} < S b H_{3}$ (Order of boiling point )
CsH < KH < NaH < LiH
The stability of the hydrides of the element from a particular group decreases with increasing atomic number (going down the group )
$C H_{4} < N H_{3} < H_{2} O$
Dipole moment depends upon the different between the electronegativitiies of the bonded atoms, and the internucler separation.
$P H_{3} < A s H_{3} < N H_{3} < S b H_{3}$
Boiling point increase with an increase in molecular mass, $N H_{3}$ being an exception because of strong hydrogen bonding
Cl < S < N < O < F
The strength of hydrogen bonding depends upon the electrongativity and the size. Higher electronegativity and smaller size increases the strength of hydrogen bonding

Suggest Corrections

Similar questions

S i F_{4} < S i C l_{4} < S i B r_{4} < S i I_{4}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

15

P H_{3} < A s H_{3} < N H_{3} < S b H_{3} < B i H_{3}

H

N H_{3}

S b

N H_{3} > P H_{3} > A s H_{3} > S b H_{3} > B i H_{3}

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