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Question

Choose the correct option.

A
ΔDEFΔPRQ
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B
ΔFEDΔRQP
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C
ΔDEFΔPQR
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D
ΔDEFΔRQP
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Solution

The correct option is D ΔDEFΔRQP

Given: DE = 2.5 cm, DF = 3 cmand EF = 2 cm

PQ = 4 cm, PR = 6 cm andQR = 5 cm

In ΔDEF and ΔPQR,

DEQR=2.55=12

DFPR=36=12

EFPQ=24=12

ΔDEFΔRQP(By SSS similarity criterion)


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Criteria for Similarity of Triangles
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