Choose the correct option.
Given: DE = 2.5 cm, DF = 3 cmand EF = 2 cm
PQ = 4 cm, PR = 6 cm andQR = 5 cm
In ΔDEF and ΔPQR,
DEQR=2.55=12 DFPR=36=12
EFPQ=24=12
∴ΔDEF∼ΔRQP(By SSS similarity criterion)