Question

Choose the correct option for the total pressure (in atm.) in a mixture of $4g{O}_2\text{and}2g{H}_2$ confined in a total volume of one litre at $0^{\circ }C$ is :

$[\text{Given}R=0.082L\text{atm}mo{l}^1{K}^{-1},T=273K]$

• A. $26.02$
• B. $2.518$
• C. $2.602$
• D. $25.18$

Answer 1

The correct option is D $25.18$

No. of Moles $O_2$, $n_{O_2}=\frac{4}{32}=\frac{1}{8}$
No. of Moles of $H_2$, $n_{H_2}=\frac{2}{2}=1$
Total No. of Moles, $n_t=\frac{1}{8}+1=\frac{9}{8}$
As We Know, $P_{t}V=n_{t}RT$

Total Pressure, $P_t=\frac{\frac{9}{8}\times 0.082\times 273}{1}=25.18\text{atm}$