Three voltmeters, all having different resistances, are joined as shown in the figure. When some potential difference is applied across A and B, their readings are V1,V2,V3:
A
V1=V2
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B
V1≠V2
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C
V1+V2=V3
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D
V1+V2>V3
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Solution
The correct options are BV1≠V2 CV1+V2=V3 The potential difference across AB is given by [VAB=V1+V2=V3] Now, current through the upper branch is flowing through [V1] and [V2] But as their resistances are different their readings won't be equal.