Choose the correct option regarding change in oxidation number of the underlined atom in the following conversion.

$H_{2} S - - O_{5} + 2 K I \to K_{2} S O_{4} + H_{2} O + I_{2}$

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No Change

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Solution

The correct option is D No Change

No change in oxidation state of $S$ takes place. Since, in $H_{2} S O_{5}$ (since it has a peroxy linkage), the oxidation state of sulphur is $+ 6$ while in $K_{2} S O_{4}$ also, the oxidation state of sulphur is $+ 6$ .

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Similar questions

M n - -- - O_{4}^{-} + 3 O H^{-} \to M n O_{2} + H_{2} O

C a O C l_{2} - -- - + H_{2} O \to C a (O H)_{2} + C l_{2}

A s_{2} - -- - S_{3} + O H^{-} \to A s S_{4}^{3 -}

2 H N - - O_{3} \to H_{2} O + N_{2} O_{5}

(H N - - O_{2})

M n O_{4}^{⊖}

(H N - - O_{2})

I^{⊖}

I_{2}

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