Choose the correct option, regarding Charles law:

V \propto \frac{1}{T}

at constant

n and P

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{(\frac{d V}{d T})}_{P} = K

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(\frac{1}{T} - \frac{V}{T^{2}}) = 0

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None of these

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Solution

The correct option is B ${(\frac{d V}{d T})}_{P} = K$
From the ideal gas equation,
$P V = n R T$
$V = \frac{n R T}{P}$ at constant pressure and number of moles
$V = K T$
Upon differentiating,
$(d V = K d T)_{P}$
$(\frac{d V}{d T})_{P} = K$
This is the differential form of Charle's law.

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Choose the correct option, regarding Charles law:

The correct option is B (dVdT)P=KFrom the ideal gas equation, PV=nRT V=nRTP at constant pressure and number of moles V=KT Upon differentiating, (dV=KdT)P (dVdT)P=K This is the differential form of Charle's law.

The correct option is B ${(\frac{d V}{d T})}_{P} = K$
From the ideal gas equation,
$P V = n R T$
$V = \frac{n R T}{P}$ at constant pressure and number of moles
$V = K T$
Upon differentiating,
$(d V = K d T)_{P}$
$(\frac{d V}{d T})_{P} = K$
This is the differential form of Charle's law.