Question

Choose the correct option(s):
$\frac{(3x^2+1)}{\left(3x^2\right)}$.

• A. True
• B. False
• C. At x=2,Value of fraction = $\frac{11}{12}$
• D. At x=3,Value of fraction = $\frac{28}{27}$

Answer 1

Answer: (A), (D)

The correct options are
A

True

D

At x=3,Value of fraction = $\frac{28}{27}$

$\frac{3x^2+1}{3x^2}=1+\frac{1}{3x^2}$

(A)$1+\frac{1}{3}=\frac{4}{3}$

(B) 1+ $\frac{1}{3\times 4\times 4}=1+\frac{1}{48}=\frac{49}{48}$

(C) $1+\frac{1}{3\times 2\times 2}=1+\frac{1}{12}=\frac{13}{12}$

(D) $1+\frac{1}{3\times 3\times 3}=1+\frac{1}{27}=\frac{28}{27}$