Choose the correct option.
Statement 1:(p∧∼q)∧(∼p∧q) is a fallacy.
Statement 2:(p⇒q)⇔(∼q⇒∼p) is a tautology.
A
Both the statements are TRUE and STATEMENT 2 is the correct explanation of STATEMENT 1.
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B
Both the statements are TRUE but STATEMENT 2 is NOT the correct explanation of STATEMENT 1.
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C
STATEMENT 1 is TRUE and STATEMENT 2 is FALSE.
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D
STATEMENT 1 is FALSE and STATEMENT 2 is TRUE.
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Solution
The correct option is B Both the statements are TRUE but STATEMENT 2 is NOT the correct explanation of STATEMENT 1. Statement 1:(p∧∼q)∧(∼p∧q)
Using Set Theory approach, this can be expressed as: (P∩Qc)∩(Pc∩Q)
Clearly, the resultant is ϕ.
Hence, statement 1 is a fallacy.
Statement 2:(p⇒q)⇔(∼q⇒∼p)
Clearly, (∼q⇒∼p) is a contra-positive of (p⇒q) and vice-versa.
Hence, statement 2 is a tautology.