Choose the correct option which can represent Snell's law for a given set of media of air and water. Here $n, θ$ represents the refractive index of the medium and the incident angle respectively.

n_{a i r} sin (θ_{a i r}) = n_{w a t e r} sin (θ_{w a t e r})

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n_{a i r} sin (θ_{w a t e r}) = n_{w a t e r} sin (θ_{a i r})

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n_{a i r} sin (θ_{a i r}) n_{w a t e r} sin (θ_{w a t e r}) = 1

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n_{a i r} n_{w a t e r} = sin (θ_{w a t e r}) sin (θ_{a i r})

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Solution

The correct option is A $n_{a i r} sin (θ_{a i r}) = n_{w a t e r} sin (θ_{w a t e r})$
According to the Snell's Law of refraction,
$\frac{n_{a i r}}{n_{w a t e r}} = \frac{sin (θ_{w a t e r})}{sin (θ_{a i r})}$
where:
$n_{a i r}, n_{w a t e r} :$ Refractive index of air and water respectively.
$θ_{a i r}, θ_{w a t e r} :$ Angle of ray with normal in air, water respectively.

$⟹ n_{a i r} sin (θ_{a i r}) = n_{w a t e r} sin (θ_{w a t e r})$

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Choose the correct option which can represent Snell's law for a given set of media of air and water. Here n, θ represents the refractive index of the medium and the incident angle respectively.

Choose the correct option which can represent Snell's law for a given set of media of air and water. Here $n, θ$ represents the refractive index of the medium and the incident angle respectively.