Question

Choose the correct option:

$Zn{OH}_2+$ ___ $\to ZnS{O}_4+2H_{2}O$

• A. $HCl$
• B. $H_2$
• C. $H_{2}S{O}_4$
• D. $Zn$

Answer 1

The correct option is C $H_{2}S{O}_4$

The products formed here are $ZnS{O}_4$ (salt) and $H_{2}O$(water). These are formed as the products of a neutralisation reaction, i.e., when an acid and a base react.

Here, $Zn(OH{)}_2$ is one of the reactants and is a base. So, the acid we are looking for contains a sulphate ion ${S{O}_4}^{2-}$. Among the given options, only $H_{2}S{O}_4$ contains a sulphate ion. So, the correct option is $H_{2}S{O}_4$ (sulphuric acid).

$Zn{\left(OH\right)}_2+H_{2}S{O}_4\to ZnS{O}_4+2H_{2}O$